Question

Two years ago, father was 5 times passed old as his son. Two years later, his age will be 8 more then 3times the age of the son. Find the present age of father and son

Answer 1

LET THE PRESENT AGE OF FATHER BE "x" AND SON BE "y"
ACC. TO QUES --->
(x-2)=5(y-2)
x-2=5y-10
x-2+10-5y=0
x-5y+8=0
x-5y=-8. ------------(1)

(x+8)=3(y+8)
x+8=3y+24=0
x-3y-16=0
x-3y=16. ---------(2)

NOW,
x-5y=-8
x-3y=-16
(-) (+). (+). (SUBTRACTING)
________
2y=8
y=4

PUTTING y=4 IN EQUATION (1).
x-5y=-8
x-5*4=-8
x-20=-8
x=-8+20
x=12

ANSWER-----> PRESENT AGE OF FATHER IS 12 AND SON IS 4.....



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