Question

A particle starts from rest with constant acceleration of4m/s*s the displacement of the particle in 3rd half second is equal to

Answer 1

Answer:

4/3=1.3333 second

Explanation:

acceleration=total distance /total time

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Displacement=12\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Acceleration(a) = {4 \: m/s}^{2} \\ \\ \tt: \implies Time(t) = 3\frac{1}{2} \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Displacement(s) = ?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = u + \frac{a}{2} (2n - 1) \\ \\ \tt: \implies s = 0 + \frac{4}{2} (2 \times \frac{7}{2} - 1) \\ \\ \tt: \implies s =2 \times (7 - 1) \\ \\ \tt: \implies s = 2 \times 6 \\ \\ \green{\tt: \implies s = 12 \: m} \\ \\ \green{\tt \therefore Displacement \: of \: particle \: is \: 12 \: m } \\ \\ \blue{ \boxed{ \bold{Some \: related \: formula}}} \\ \\ \orange{\tt \circ \: s = ut + \frac{1}{2} {at}^{2} } \\ \\ \orange{\tt \circ \: v = u + {at}} \\ \\ \orange{\tt \circ \: {v}^{2} = {u}^{2} + 2{as} }$