Question

A particle starts moving along x -
axis, with constant velocity 4m/s. After 2s from the start of motion of the first particle, another particle starts in the same direction, with the same position
with constant velocity of 6m/s. calculate the time at which second particle will catch the first
particle.
1) 5s
2) 3s
3) 2s
4) 6s
​

Answer 1

Answer:

answer will be 5 second hope it will help you

Answer 2

Answer: Second particle catches the first particle after 6 seconds.

Explanation:

Let the second particle catch the first particle at t second.

Therefore, after t seconds both particle will have travelled same distance.

Distance travelled by first particle = 4t

Distance travelled by second particle = 6(t-2)

$4t = 6(t-2)$

$4t= 6t -12$

$2t = 12$

t = 6

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