Question

A particle starts moving from the position of rest under constant acceleration if it travels a distance x in the seconds and y in the next two seconds then what is the relation between x and y Give ans fast plzzzz

Answer 1

Answer:

initially velocity is zero, and acceleration is a, so distance covered in 1 sec is x= $\dfrac {1}{2}a1^2 = 0.5a$

now distance covered in total 3 sec is $x+y = \dfrac{1}{2} a 3^2 = \dfrac{9}{2} = 4.5a$

x= 0.5a

y= 4x