A particle starts moving with acceleration 2m/s distance travelled by it in 5th half second is: A1.25 m b 2.25 m c 6.25 m d 30.25 mAnswer is b.but how?
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Answered by
584
Distance travelled in 5th half second = Distance travelled in 2.5 seconds - Distance travelled in 2 seconds
= 0.5a (t₁² - t₂²)
= 0.5 * 2 * (2.5² - 2²)
= 2.25m
= 0.5a (t₁² - t₂²)
= 0.5 * 2 * (2.5² - 2²)
= 2.25m
Answered by
213
Answer:
Yes the answer is option b. 2.25 m which is solved using instantaneous distant formula.
Explanation:
The particles moves with a given acceleration, so the displacement of the particle in 5th half second will be given by the formula of instantaneous displacement.
Given is the acceleration a = 2
Time t = 5th half sec = = 2.5 sec as
and = 5th half sec – one half sec = 4th half sec =
= 2 sec
From the instantaneous displacement formula, we have –
The displacement in half second be 2.25 m.
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