A particle starts with a initial velocity of 8m/sec and moves along a straight line .its acceleration at any time t after start, is given by the expression a-bt where a and b are constants. determine the equation for displacement , if the particle covers a distance of 40m in 5sec and stops.
Answers
Answered by
3
Answer:
at t=5 , v=0.
put this in eqn of v. you'll get eqn 1 in a and b
at t=5, x= 40
put it in eqn of x, u get eqn 2 in a and b.
solve eqn 1 and 2 to get a,b and substitute them in eqn 2.
you get expression for x
Attachments:
Answered by
0
diagonal across a square with sides of one unit of length; this follows the Pythagorean theorem. It was probably the first number known to be irrational.[citation needed]
As a good rational approximation for the square root of two, with a reasonably small denominator, the fraction 99/70 (≈ 1.4142857) is sometimes used.
The sequence A002193 in the OEIS consists of the digits in the decimal expansion of the square root of 2, here truncated to 65 decimal places:
Similar questions