Question

A particle starts with a velocity of 5ms-1 and moves with uniform acceleration of 2.5ms -2 . It's velocity after 4s is

Answer 1

Answer:

15 m / sec

Explanation:

Given :

Initial velocity ( u ) = 5 m / sec

Time ( t ) = 4 sec

Acceleration ( a ) = 2.5 m / sec²

We have to find Final velocity ( v )  :

We have :

v = u + a t

Putting values here :

v = 5 + 2.5 × 4

v = 5 + 10

v = 15 m / sec .

Hence the final velocity of particle is 15 m / sec .

Answer 2

Solution:

Given:

➔ Initial velocity = 5 m/s

➔ Time = 4 sec

➔ Acceleration = 2.5 m/s²

To find:

➔ Final velocity

Formula used:

➔ First equation of motion, v = u + at

Now, we will put the values in the formula.

➔ v = u + at

➔ v = 5 + 2.5 × 4

➔ v = 5 + 10

➔ v = 15 m/s

Hence, final velocity of particle is 15 m/s.

Extra Info:

Equations of Motions:

➔ v = u + at         [1st Equation of motion]

➔ s = ut + ½at²   [2nd Equation of motion]

➔ v² = u² + 2as   [3rd Equation of motion]