Question

A particle starts with an initial velocity 2.5m/s along a straight line its acceleration at the rate 0.5 m/s .How much distance will it cover to reach the velocity 7.5 m/s

Answer 1

Explanation:

u =2.5 m/sec, a = 0.5 m/sec², v = 7.5 m/sec, s = ?

v² - u² = 2as

7.5² - 2.5² = 2×o.5×s

50 = 2×0.5×s

therefore s = 50/(2×0.5) => 50 m

Answer 2

Answer:

54.68m

Explanation:

. initial velocity =. 2.5ms

acceleration = 0.5

final velocity is 7.5

Then use

v^2=u^2+2as equation

v= final velocity

u=initail velocity

a= acceleration

s=distance

(7.5)^2=(2.5)^2+ 2*0.5*s