a particle starts with velocity 10ms¯¹. The acceleration of the particle is 2ms¯² find the displacement of the particle at time=2sec?
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S= ut+1/2at^2
S=10×2+1/2×2×4
S= 20+4
=24 meter
S=10×2+1/2×2×4
S= 20+4
=24 meter
Answered by
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initial velocity(u) = 10
acceleration(a)=2
time( t)= 2
displacement(s)= ut+(at^ 2)/2 =20+4 =24 m
acceleration(a)=2
time( t)= 2
displacement(s)= ut+(at^ 2)/2 =20+4 =24 m
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