A particle strikes elastically with another particle with velocity week after collision it moves with half the
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Answer:3v/2
Explanation:Aacording to newton's law of restitution (velocity of sepration)=e*(velocity of approch )
So, e for elastic body is 1 and then, u1-u2=v2-v1
U2 is given zero and u1 is v , v1 is given v/2 so relation becomes v=v2-v/2 , by solvibg u get v2=3v/2 , thanks
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Answer:3v/2
Explanation:Aacording to newton's law of restitution (velocity of sepration)=e*(velocity of approch )
So, e for elastic body is 1 and then, u1-u2=v2-v1
U2 is given zero and u1 is v , v1 is given v/2 so relation becomes v=v2-v/2 , by solvibg u get v2=3v/2 , thanks
Explanation:
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