Physics, asked by charvi415, 11 months ago

A particle strikes elastically with another particle with velocity week after collision it moves with half the

Answers

Answered by Ronit7988
12

Answer:3v/2

Explanation:Aacording to newton's law of restitution (velocity of sepration)=e*(velocity of approch )

So, e for elastic body is 1 and then, u1-u2=v2-v1

U2 is given zero and u1 is v , v1 is given v/2 so relation becomes v=v2-v/2 , by solvibg u get v2=3v/2 , thanks

Answered by tlhnizam
0

Answer:

Answer:3v/2

Explanation:Aacording to newton's law of restitution (velocity of sepration)=e*(velocity of approch )

So, e for elastic body is 1 and then, u1-u2=v2-v1

U2 is given zero and u1 is v , v1 is given v/2 so relation becomes v=v2-v/2 , by solvibg u get v2=3v/2 , thanks

Explanation:

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