Question

A particle takes 6.28 seconds to complete one Revolution its angular speed is

Answer 1

Hii friend,

Here is your answer...

We know the formula,
$omega = 2\pi \ \: t$
omega =>2π/t

:-omega => 2×3.14/6.28

Angular velocity =>1 rad /s.

Hope this helps you a little!!!

Answer 2

$\red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

Angular speed or angular velocity is the ratio of angular displacement to time taken. It is defined by the equation :

$\bigstar \: \orange{\mid{\underline{\overline{\textbf{omega = 2pi/ \:∆t }}}\mid}}$

In this equation :

• Omega = Angular velocity or speed
• ∆t = Change in time.
• 2π rad = One revolution.

Now angular speed is measured in rad /s.

$\blue{\mid{\underline{\overline{\textbf{Coming to question :-}}}\mid}}$

In this question we have been given that a particle completes 1 revolution in 6.28 s, it's angular velocity or speed is not known we have to calculate it.

Now in this case :

• Omega = ?
• ∆t = 6.28
• displacement = 1 revolution = 2π rad.

Now after inputting these values in the expression we get :

$\mapsto \: omega = \frac{2.8 \times 3.14}{6.28}$

$\mapsto \: omega = 2 \times \cancel \frac{3.14}{6.28}$

$\mapsto \: omega = \frac{2}{2} = 1rad/s$

Therefore the angular speed of particle is 1rad/s.

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BY SCIVIBHANSHU

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