Question

A particle thrown up vertically reaches its highest point in time
t1 and returns to the ground in a further time t2. The air resistance
exerts a constant force on the particle opposite to its direction of
motion.
a. t1>t2
b. t1=t2
c. t2>t1
(d) May be (a) or (c) depending on the ratio of the force of air
resistance to the weight of the particle.

Answer 1

Answer:

t1 = t2

Explanation:

A particle thrown up vertically reaches its highest point in time

t1 and returns to the ground in a further time t2. The air resistance

exerts a constant force on the particle opposite to its direction of

motion.

t1 = t2

as there are only two forces acting on the particle

one is air resistance  & other is gravity

air resistance is opposite to direction of motion so always opposite.

Gravity is Fixed acceleration / deceleration

Hence Object will accelerate decelerate with same speed

And reaches back with same velocity as thrown upwards and hence

t1 = t2