Question

a particle thrown vertically upward reaches a height 10m at two times ie t=2s and t=10 s.find tine of flight of particle?​

Answer 1

Explanation:

u=distance/time

u=10/8m/s

then, time of flight =2u/g

so, t=2×10÷8×10=0.25

Answer 2

Answer:

14 s

Explanation:

the time to reach max height = 2 + 10/2 = 7 s = 2u/g = u/5 , u = 35m/s

the time of flight = 2x7 = 14 s