Question

a particle travel 100 meter after starting from rest in 10 seconds . its acceleration is​

Answer 1

Answer:

s = 100m

u = 0

t = 10s

a = ?

$s = ut + 1/2a {t}^{2}$

100 = 5 × 10 a

100/50 = a

$a \: = 2m/ {s}^{2}$

Answer 2

Answer:

acceleration= 1ms-2

Explanation:

first we found the speed of particle after travelling 100metres in 10 seconds....

S= D/T

S = 100/10

S = 10 ms-1

by explaining through motion first law

v = u + at

10 = 0 + a(10) { v-s and u is at rest }

a = 10/10

a = 1 ms-2

ANSWER.......