Question

a particle travel in a circle of radius 20 cm at a speed that uniformly increase from 5 m/s to 6m/s in 2 seconds then find thr an angular acceleration

Answer 1

Initial tangential speed = 5 m/s
Final tangential speed = 6 m/s
Time taken = 2 s.

Tangential acceleration is the rate of change of speed.
$a_t= \frac{v-u}{t} = \frac{6-5}{2} = 0.5 ms^{-2}$

Radius of the circle, R = 20 cm = 0.2 m

Angular acceleration , α = $\frac{a_t}{R} = \frac{0.5}{0.2} = 2.5 rad s^{-2}$