A particle Travels 10 m in 5 second and 10 m in next 3 seconds assuming constant acceleration what distance will it cover in next two seconds
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1/2at^2=10 since u=0
putting t=5 a=4/5
for t=10 s=1/2×4/5×100=40m
distance in 8sec=10+10=20m
distance in later two second =40-20=20m
so 20m is the answer
putting t=5 a=4/5
for t=10 s=1/2×4/5×100=40m
distance in 8sec=10+10=20m
distance in later two second =40-20=20m
so 20m is the answer
piyushkumarpandey:
please mark it as brainliesr
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