A particle travels half of the time with constant speed 2m/s. in the remaining half time it travels 1/4th distance with constant speed 4m/s and 3/4th distance with 6m/s. find average speed during the entire journey
Answers
Answer:
11/3 = 3.67 m/s
Explanation:
A particle travels half of the time with constant speed 2m/s. in the remaining half time it travels 1/4th distance with constant speed 4m/s and 3/4th distance with 6m/s. find average speed during the entire journey
Let Say Total Journey = D m
Total Time = T
Average Speed During Journey = D/T
Distance Traveled for Half Time = 2(T/2) = T m
in Remaining T/2 time He will cover D - T m
1/4th Distance = (D -T)/4
Speed = 4 m/s
Time = (D -T)/16
3/4th Distance = 3(D -T)/4
Speed = 6 m/s
Time = (D -T)/8
(D -T)/16 + (D -T)/8 = T/2
Multiplying by 16 both sides
=> D - T + 2(D - T) = 8T
=> 3D = 11T
=> D/T = 11/3
average speed during the entire journey = 11/3 = 3.67 m/s
Answer:
11/3 m/s
Explanation:
2t = d1…..(i)
[d/4] /4+[3d/4] /6 = t
⇒ 3d/16 = t…..(ii)
- Average velocity = total distance/total time
=[d1+d2] / 2t = [2t+16t/3] / 2t
= 11 / 3 m/s