Question

a particle undergoes a displacement of 3m due north and 4m due east . the net displacement is ?​

Answer 1

The net displacement of the particle is equal to 5 metre.

Explanation:

• This is in accordance to the Pythagoras theorem fullstuff here the displacement of the particle in north direction by 3 metres and in the east direction by four forms the two arms of the the right angle triangle. In the resultant displacement will take place in the north east direction.
• This is because displacement is is a vector quantity and has both direction as well as magnitude. The magnitude of the the displacement vector is equal to $\sqrt{(3² + 4²)}$ = 5meter

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Answer 2

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