Question

A particle weighs 120 N on the surface of earth. On what height above the earth's surface would its weight be 30N? (Re=6400 km)

Answer 1

mg = 120 N
mg'= 30 N

$new \: weight \: = {(\: 1 + \frac{h}{r} ) }^{ - 2} \times o \:ld \: wight$

substituting values,
$30 \: = {(1 + \frac{h}{6400}) }^{ - 2} \times 120$

on further simplification,
${(1 + \frac{h}{6400})}^{ - 2} = \frac{1}{4}$


$1 + \frac{h}{6400} = 2$
$h = 6400 = radius \: of \: earth$

Answer 2

Answer:

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