A particle weighs 120 n on the surface of the earth.at what height above the earth's surface will its weigh be 30 n?
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mg = 120 N
At height h
Wieght = mg’
mg’ = mg * (r / (r + h))^2
30 = 120 * (6400 / (6400 + h))^2
1/4 = (6400 / (6400 + h))^2
1/2 = 6400 / (6400 + h)
6400 + h = 12800
h = 6400 m
Height at which body’s wieght is 30 N is 6.4 km
At height h
Wieght = mg’
mg’ = mg * (r / (r + h))^2
30 = 120 * (6400 / (6400 + h))^2
1/4 = (6400 / (6400 + h))^2
1/2 = 6400 / (6400 + h)
6400 + h = 12800
h = 6400 m
Height at which body’s wieght is 30 N is 6.4 km
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