Question

A particle with a charge of 2.5C is taken from a point A at a potential of 60V to another point B at a

potential of 130V. Calculate the work done.




HELP REQUIRED​

Answer 1

Explanation:

charge on particle=2.5c

potential of a=60V

potential of b=130V

we know,

potential difference= work done/ charge

so potential difference=130-60=70

now putting value of potential difference and charge in the pd formula which is above

70=work/2.5

work=70*2.5

work= 175 joules

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Answer 2

Explanation:

charge on particle=2.5c

potential of a=60V

potential of b=130V

potential difference= work done/ charge

so potential difference=130-60=70

70=work/2.5

work=70*2.5

work= 175 joules