Question

A particle with a velocity of 2 metre per second moves along a straight line with a constant acceleration of 0.2 metre per second square find the displacement of the particle in 10 seconds.​

Answer 1

Answer:

Explanation:

s= ut + 1/2×at^2

 = 2×10 + 1/2×0.2×10^2

=20+ 10

= 30 m

Answer 2

Given:-

• Initial velocity of particles (u) = 2m/s

• Acceleration of the particle (a) = 0.2m/s²

• Time Taken by particle (t) = 10s.

To Find :-

• Displacement of the particle (s) .

Solution :-

By using 2nd equation of the motion

⟹ s = ut +1/2at²

Putting all the values which is given above

⟹ s = 2 × 10 + 1/2 ×0.2 × 10²

⟹ s = 20 + 1/2 × 0.2 ×100

⟹ s = 20 + 0.2 × 50

⟹ s = 20 + 10

⟹ s = 30 m

Therefore,the displacement of the particle after 10s is 30m.

Extra Information !!

Some equation of motion are

⟹ v = u +at

⟹s = ut +1/2at².

⟹ v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken