Physics, asked by sarveshy, 1 year ago

A particle X moving with a constant velocity u crosses a point 0. At the same instant another particle F
starts from rest from O with a constant acceleration a. The maximum separation between them before they
meet is
(a) u /2a
(b) ula
2u/a
(d) u²/4a​

Answers

Answered by Anonymous
17

Answer:

(a)  \frac{u}{2a} is right.

Explanation:

maximum distance will be when both of them have same velocity because after that point of time velocity of particle F will be more then that of particle x so distance between then starts decreasing.

t=\frac{u}{a}

distance covered by X till this time is  S_{1} =u*\frac{u}{a}

distance covered by F till that time is  S_{2} =\frac{1}{2}a \frac{u^2}{a^{2} }= \frac{u^{2} }{2a}

maximum distance between them S_{1} -S_{2} =\frac{u^{2} }{2a}

so option A is correct.  

Answered by varshini1101
1

Heya!!

Here is your answer⬇️⬇️

A particle X moving with constant velocity u crosses a point O. At the same instant another particle F starts from rest from O with a constant acceleration.

The maximum separation between them before they are u/2a.

Hope this helps you❤

Similar questions