A particular car can go from rest to 90 km/h in 10 s. What is the acceleration ?
Answers
Answer:
Let’s review the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory):
s = ut + ½at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.
In this case, we know u = 0, v = 60km/h = 16.67m/s, t = 10s and we want to find a, so we use equation (3)
v = u + at
16.67 = 0 + 10t, so t = 16.67/10 = 1.667m/s^2
The acceleration is 1.667m/s^2.
Explanation:
like this calculate the 90
Answer:
Let’s review the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory):
s = ut + ½at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.
In this case, we know u = 0, v = 60km/h = 16.67m/s, t = 10s and we want to find a, so we use equation (3)
v = u + at
16.67 = 0 + 10t, so t = 16.67/10 = 1.667m/s^2
The acceleration is 1.667m/s^2.