a particular liquid freezes at -42 c.the current temperature of the liquid is 30 c. the liquid is cooled in such a way that it temperature decreases at a constant rate. if it takes 12m for the liquid to frees, then at what rate the liquid is cooled?
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Answer:
Time taken by ice to grow a thickness of
t=
2Kθ
eL
y
2
Hence time interval to change thickness from 0 to y, from y to 2y and so on will be in the ratio.
Δt
1
:Δt
2
:Δt
3
∴=(1−0
2
):(2
2
−1
2
):(3
2
−2
2
)
Δt
1
:Δt
2
:Δt
3
=1:3:5
According to question =Δt
1
< terims
Δt
2
=3ΔH
=3×12=36min.
Explanation:
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