Question

A particular transmitter of aakashvani broadcasts at 420.5m wavelength. Given the speed of radio waves 3×10ms-1. Calculate the frequency at which the radio station broadcasts its programme.

Answer 1

Velocity = frequency times
wavelength:
v=fλ
3×10^8= f × 420.5
f = 3×10^8 /420.5 = 7.13436 × 10^5

Answer 2

Answer:

The frequency of the radio waves is $7.13 \times 10^{2}$ kHz.

Explanation:

Given:-

Radio wave propagation speed (v)= 3 × $10^{8}$ m/s

The wavelength of the radio waves ( λ ) = 420.5m.

To Calculate :

The radio station's broadcasting frequency for its programming.

Calculations:

The equation that connects frequency, speed, and wavelength is as follows:

v = λf

where λ is the wavelength, v is the velocity and f is the frequency.

Since we need to calculate the frequency of the wave. we modify the formula accordingly,

Thus, we have

So, f = $\frac{v}{\lambda}$

Now, putting all the values in the above formula, we get

$f = \frac{3 \times10^{8} }{420.5} = 7.13 \times 10^{2}kHz$

Hence, the radio waves' frequency is $7.13 \times 10^{2}$ kHz.

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