A passenger takes 2 hours more than an express train to travel a distance of 120 km from station A to station Y. The speed of the passenger train is less than the express train by 10 kilometre/hour. Find average speed of each train.
Answers
Answer: speed of the passenger train is 40km/h
Answer: speed of the passenger train is 40km/hSpeed of the express train is 60km/h
Answer: speed of the passenger train is 40km/hSpeed of the express train is 60km/hStep-by-step explanation: Let the speed of the passenger train is x km/h
Speed of the express train is y km/h
Speed of the express train is y km/h A/c to question,
Speed of the express train is y km/h A/c to question,Passenger train takes 2 hours more than an express train to travel a distance of 240km. Also the speed of the express train is more than that of the passenger train by 20km/h
Speed of the express train is y km/h A/c to question,Passenger train takes 2 hours more than an express train to travel a distance of 240km. Also the speed of the express train is more than that of the passenger train by 20km/he.g., x + 20 = y .............(1)
Speed of the express train is y km/h A/c to question,Passenger train takes 2 hours more than an express train to travel a distance of 240km. Also the speed of the express train is more than that of the passenger train by 20km/he.g., x + 20 = y .............(1)240/x = 240/y + 2 .........(2) [ time = distance/speed ]
Speed of the express train is y km/h A/c to question,Passenger train takes 2 hours more than an express train to travel a distance of 240km. Also the speed of the express train is more than that of the passenger train by 20km/he.g., x + 20 = y .............(1)240/x = 240/y + 2 .........(2) [ time = distance/speed ] ⇒ 240/x - 240/(x +20) = 2 [ putting equation (1) in equation (2); ]
Speed of the express train is y km/h A/c to question,Passenger train takes 2 hours more than an express train to travel a distance of 240km. Also the speed of the express train is more than that of the passenger train by 20km/he.g., x + 20 = y .............(1)240/x = 240/y + 2 .........(2) [ time = distance/speed ] ⇒ 240/x - 240/(x +20) = 2 [ putting equation (1) in equation (2); ]⇒ 240 [ (x + 20 - x)/x(x +20) ] = 2
⇒ 120 [ 20/(x² + 20x) ] = 1
⇒ 120 × 20 = x² + 20x
⇒ x² + 20x - 2400 = 0
⇒ x² + 60x - 40x -2400 = 0
⇒ x(x + 60) -40(x + 60) = 0
⇒ (x + 60)(x - 40) = 0
⇒ x = 40 and -60 but speed can’t be negative so, x ≠
-60 km/h
Hence, speed of the passenger train is 40km/h
And speed of the express train is 60km/h
Answer:
speed of the passenger train is 20km/h
Speed of the express train is 30km/h
Step-by-step explanation: Let the speed of the passenger train is x km/h
Speed of the express train is y km/h
A/c to question,
Passenger train takes 2 hours more than an express train to travel a distance of 120km. Also the speed of the express train is more than that of the passenger train by 10km/h
e.g., x + 10 = y .............(1)
120/x = 120/y + 2 .........(2) [ time = distance/speed ]
⇒ 120/x - 120/(x +10) = 2 [ putting equation (1) in equation (2); ]
⇒ 120 [ (x + 10 - x)/x(x +10) ] = 2
⇒ 60 [ 10/(x² + 10x) ] = 1
⇒ 60 × 10 = x² + 10x
⇒ x² + 10x - 600 = 0
⇒ x² + 30x - 20x -600 = 0
⇒ x(x + 30) -20(x + 30) = 0
⇒ (x + 30)(x - 20) = 0
⇒ x = 30 and -20 but speed can’t be negative so, x ≠ -60 km/h
Hence, speed of the passenger train is 20km/h
And speed of the express train is 30km/h