A passenger train covers the distance between stations x and y, 50 minutes faster than a goods train. find this distance if the average speed of the passenger train is 60 kmph and that of the goods train is 20 kmph.
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Solution:
Let 'P' be the distance between the stations X and Y.
Time taken by the passenger train to cover the distance 'P' =P60 hour
Time taken by the goods train to cover the distance 'P =P20 hour
Time difference between these two trains is given by 50 minutes or 5060 hour
⇒ P20–P60=5060
P[(60−20)(20×60)]=5060
P= 25 kms
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Solution:
Let 'P' be the distance between the stations X and Y.
Time taken by the passenger train to cover the distance 'P' =P60 hour
Time taken by the goods train to cover the distance 'P =P20 hour
Time difference between these two trains is given by 50 minutes or 5060 hour
⇒ P20–P60=5060
P[(60−20)(20×60)]=5060
P= 25 kms
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