Math, asked by angelfernandes6990, 1 year ago

A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the special character is at the end of the password, how many possibilities are there? a. 175,760 b. 456,976 c. 703,040 d. 1,679,616

Answers

Answered by vartikaagarwal
23
This is an interesting question which can be cracked by basic knowledge of permutations and combinations.

Given that the password is a mixture of alphabet(say Á') and special characters (say 'S'). Also, as letters can be repeated and the special character is always at end, the maximum possible passwords possible are-
                              
 Password:-                                                  _           _           _           _

Combination required:-                              A          A           A           S
Maximum possible combinations:           26         26          26         10

So the maximum possibilities would be a multiple of max possibilities for each space. Hence, 

                          26*26*26*10 = 175760
 
Ans:- 175,760 is the total number of possible combinations.
Answered by ciarareagan98
7

Answer:

A

Step-by-step explanation:

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