a path 2 m wide is built along the border and inside a square garden of side 40 Find the area of the path
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Step-by-step explanation:
ANSWER
Let ABCD, the square garden of side= 40 m.
PQRS is the region inside the garden.
so,
PQ = (40 -2-2 ) = 36 m
also
PS = ( 40 – 2 – 2 ) = 36 m
(i) Area of the path = Area of ABCD – Area of PQRS
= [( 40 x 40) – (36 x 36)]
= 1600 – 1296
= 304 sq.m
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