Question

A path 2m wide runs around outside a square park of side 60m. Find the area of the path. ​

Answer 1

Answer:

Step-by-step explanation: ABCD is a park of  [side = 3 cm ]

now

Portion outside (EFGH) is a running path of width = 60 cm

area of running path = area of ABCD - area of EFGH

length of side EFGH =60−3=57cm

Then

area of running path =(60)  ²  −(57) ²

area=3600-3249

area=351

Answer 2

Area of path = Area of bigger square - Area of smaller square

Side of the smaller square = Side of the bigger square - 2(width of the path)

= 100 - 2(5)

= 90m

Area of the path = (100)² - (90)² = 10000 - 8100 = 1900 sq cm

Cost of cementing at the rate of Rs. 250 per 10m² = 250 × 190 = Rs. 47500