A path of uniform width runs around a square park of side 18 m if the area of the path is 37m square find its width
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there will be 2 squares figures.
inner square and outer square.
Area of inner square=18×18=326sqm.
Area of outer square=area of inner +area of path.
=324+37=361m.
so Area of outer square=side^2.
361=side ^2
√361=side
19=side
inner square and outer square.
Area of inner square=18×18=326sqm.
Area of outer square=area of inner +area of path.
=324+37=361m.
so Area of outer square=side^2.
361=side ^2
√361=side
19=side
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0.5 answer ana chahiye nhi to sir pitenge
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