Question

a patient in a hospital is given soup daily in a cylindrical bowl of diameter 7m if the bowl is failed with soup to a height of 4cm, how much soup the hospital has to prepare daily to serve 250 patient

Answer 1

d = 7cm =>. r = 3.5 cm

h = 4 cm

soup given to 1 patient = vol of soup

= π r²h

=[(22/7)×(3.5)² × 4]cm³

= 154 cm³

soup to be prepared for 250 patients = (250×154) cm³ = 38500 cm³ = 38.5L

[ 1L = 1000cm³]

Answer 2

Given :

• Diameter of bowl = 7cm
• Height of bowl = 4cm

To Find :

• Soup to be prepared to serve 250 patients.

Solution :

$\longmapsto\tt{Diameter=7cm}$

$\longmapsto\tt{Radius=\dfrac{7}{2}}$

$\longmapsto\tt{Height=4cm}$

Using Formula :

$\longmapsto\tt\boxed{Volume\:of\:Cylinder=\pi{{r}^{2}h}}$

Putting Values :

$\longmapsto\tt{\dfrac{22}{\cancel{7}}\times\dfrac{\cancel{7}}{\cancel{2}}\times\dfrac{7}{\cancel{2}}\times{\cancel{4}}}$

$\longmapsto\tt\bold{154{cm}^{3}}$

So , Volume of 1 ball is 154cm³...

Now :

$\longmapsto\tt{Volume\:of\:250\:bowls=154\times{250}}$

$\longmapsto\tt\bold{{38500cm}^{3}}$

In litres :

$\longmapsto\tt{\dfrac{38500}{1000}}$

$\longmapsto\tt\bold{38.5L}$