A pavement of width 0.5 metres was built around a square swimming pool and the area of the pavement is 49 sq metres. What is the area of the swimming pool?
A.576 sq metres
B.625 sq metres
C.529 sq metres
D.Can't be determined
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In fig the blue boundary is the one with the pavement and the orange one is the boundary of the swimming pool.
let side of pool = x
side of pool + boundary = x+1 (as 0.5 increases on both sides)
given , total area - area of pool = 49
(x+1)^2 - (x)^2 = 49
2x +1= 49
2x= 48
x = 24
area of pool = x^2 = 576
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