A peacock is sitting on a pillar 9m high. A snake at a distance of 27m from the pillar is coming to a hole at the base of the pillar. Seeing the snake, the peacock pounces upon it. If their speeds are equal then find at what distance from the hole is snake caught ?
Answers
Let AB be the pillar of height 9 meter. The peacock is sitting at point A on the pillar and B is the foot of the pillar. (.. AB = 9) Let C be the position of the snake which is at 27 meters from B. (BC = 27 and ABC = 90) As the speed of the snake and of the peacock is same they will travel the same distance in the same time... Now take a point D on BC that is equidistant from A and C. (Please note that snake is moving towards the pillar and hence B-D-C) Hence by condition 1 AD = DC = y (say) Take BD = x Now consider triangle ABD which is a right angled triangle Using Pythagorus theorem (AB + BD = AD) 9 + x = y 9 = y - x = (y-x)(y+x) 81/(y+x) = (y-x) y+x = BC = 27 Hence 81/27 = (y-x) = 3 y - x = 3 y + x = 27 Adding gives .. 2y = 30 or y = 15 x = 27 - y = 12 Thus the snake is caught at a distance of x meters or 12 meters from the hole. #hope it helps #Mark as the brainliest pls
Given :
★ A peacock is sitting on the top of the pillar, which is 9m high. From a point 27m away from the bottom of the pillar, A snake is coming to its hole at the base of the pillar. Seeing the snake the peacock ounces on it. If their speeds are equal.
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Find :
★ What distance from the hole is the snake caught.
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Concept :
★ As per the given question, the concept is finding the distance from a point to a certain point, so let us assume "x" as the difference between them.
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★ Remember that, the variable x is used here instead of word DISTANCE in our equations.
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Calculations :
→ 9² + (27)²
→ 81 + 729 + x - 54
→ 810/54
→ 15
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Finding the distance :
→ x = 15 - 3
→ x = 12 m
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★ Therefore, 12 meter is the distance from the hole.