Math, asked by zeeshanmughal2710198, 3 days ago

A pear cost x cents . An orange cost y cents less than a pear. Find the cost of four pears and half of a dozen of oranges ​

Answers

Answered by Anonymous
2

an apple costs a cents

cost of 5 apples = 5a

 

a pear costs b cents more tahn an apple

cost of 1 pear =  a+b

cost of 7 pear =7(a+b)=7a+7b

 

 

cost of 5 apples and 7 pears =5a +7a+7b =12a+7b

Answered by Anonymous
0

Answer:

Cost of a pear=x cents

Cost of an orange=(x-y) cents

Cost of 4 pears=4x cents

Half a dozen means 6 oranges

Cost of 6 oranges=6(x-y) cents

Total cost=Cost of 4 pears+Cost of 6 oranges=4x+6(x-y)=4x+6x-6y=10x-6y

Answer=10x-6y cents

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