A pebble is thrown vertically upward with a speed of20 metre per second how high will it be after 2 second
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Using the S = ut + 1/2gt^2 equation;
Here, U = 20, t = 2 & g = -10
Therefore,
20×2 + 1/2×(-10)2^2
S = 20 metres
Here, U = 20, t = 2 & g = -10
Therefore,
20×2 + 1/2×(-10)2^2
S = 20 metres
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