A pebble is thrown vertically upwards with a speed of 20 mps. how high it will be after 2s ?g=10
Answers
Answered by
1
Hi there,
Let's solve it:
S = ut + 1/2 gt^2
=20×2+1/2×-10×2^2
=20m
Let's solve it:
S = ut + 1/2 gt^2
=20×2+1/2×-10×2^2
=20m
Answered by
0
Given,
u =20m/s
t=2s
g = -10m/s2 (because object is moving upward but g is downward always)
h= ut+1/2at2
= 20 * 2s + 0.5* (-10)* (2)2
= 40 - 20
= 20 m
u =20m/s
t=2s
g = -10m/s2 (because object is moving upward but g is downward always)
h= ut+1/2at2
= 20 * 2s + 0.5* (-10)* (2)2
= 40 - 20
= 20 m
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