Question

A pebble is thrown verticaly upwards with the speed of 20m/s and an a separation of 10m/s how high will be after 2 s

Answer 1

Answer:

It will travel a height of 20m.

Explanation:

Given,

Initial Velocity (u) = 20 m/s

Final Velocity (v) = 0 m/s

Time (t) = 2 s

Acceleration (a) = (v-u)/t

= (0-20)/2

= - 20/2

= - 10 m/s^2

v^2 = u^2+2ah .... 'h' is the height

= (0)^2 = (20)^2+2( -10h )

= 0 = 400-20h

= 20h = 400

= h = 20 m

Hope this helps.