Physics, asked by mishti2106, 5 hours ago

A pebble thrown vertically upwards with an intial velocity 24m/s comes to rest in 6s. Find the decceleration.

Answers

Answered by pulakmath007
7

SOLUTION

GIVEN

A pebble thrown vertically upwards with an initial velocity 24m/s comes to rest in 6s.

TO DETERMINE

The deceleration

EVALUATION

Here it is given that a pebble thrown vertically upwards with an initial velocity 24 m/s comes to rest in 6s.

Initial velocity = u = 24 m/s

Final velocity = v = 0

Time = t = 6 sec

Thus the required acceleration

 \displaystyle \sf{ =  \frac{v - u}{t} }

 \displaystyle \sf{ =  \frac{0 - 24}{6} } \:  \: m/{s}^{2}

 \displaystyle \sf{ =  \frac{- 24}{6} } \:  \: m/{s}^{2}

 \displaystyle \sf{ =  - 4 } \:  \: m/{s}^{2}

FINAL ANSWER

The deceleration = 4 m/s²

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