Math, asked by parasharpraveen244, 2 months ago

A pedestal is constructed in the form of the frustum
of a pyramid, the sides of the square ends of the
frustum being 360 cm and 160 cm and its slant
height 260
.
.
.
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Hello Koi zinda ha to foll ow kardo ya fir thanks de do

Answers

Answered by delphinaemoin10
1

Hie there!! here's your answer!!

Answer:

1012.80

Step-by-step explanation:

The cost of construction is Rs 1012.80.

Slant height = 260 cm (Given)

Square ends of frustum = 360 cm and 160 cm {Given}

Base = (360 - 160)/2 => 100 cm

Slant height = a² + b² = c²

a² + 100² = 260²

a² = 57600

a = √57600

a = 240 cm

Therefore, height is 240 cm

Volume = h/3 ( Area 1 + Area 2 + √ Area 1 x Area 2

= 2.4/3 ( 3.6 x 3.6 + 1.6 x 1.6 + √(3.6 x 1.6) )

= 0.8 ( 17.92) = 14.336 m³

Therefore, the volume is 14.336 m³

Lateral surface area -

For one face = 1/2 × (3.6 + 1.6) x 2.6 = 6.76 m²

For four faces = 6.76 x 4 = 27.04 m²

Surface area needed to plaster:

= 1.6 x 1.6 + 27.04

= 29.6 m²

The total surface area is 42.56 m²

Cost of construction - 1 m³ = Rs 50

14.336 m³ = 50 x 14.33

= Rs 716.80

The cost of construction is Rs 716.80

Cost of plastering - 1 m² = Rs 10

Thus, for 29.6 = 29.6 x 10 = Rs 296

The cost of plastering is Rs 296

Total cost: = 716.80 + 296

= Rs 1012.80

Answered by Mysteryboy01
0

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