Question

a peice of wire 27 cm long is bent to form a traingle whose sides are in the proportion of 2 3 4 .a. what is the length of the largest side? .b. What is the length of the shortest side

Answer 1

Here you go! Hope this helps
Here x is the proportionality constant.
Perimeter of the triangle equals to the length of the wire.
Hence, 2x+3x+4x=27

Answer 2

Let the proportion be x.
Then, side of triangle are 2x, 3x and 4x.
Length of wire=Perimeter of triangle=27 cm.
Then,
Perimeter of triangle=27 cm
=>2x+3x+4x=27 (since perimeter of a triangle= sum of all the of that particular triangle)
=>9x=27
=>x=3
a. Length of shortest side =2x =2×3 =6cm
b. Length of the longest side =4x =4×3 =12 cm