A pendulum bob has speed of 3m/s while passing through its lowest position. what is its speed when it makes an angle of 60°with vertical.
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answer of thease question is 1.5
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According to the given details, the pendulum bob has the speed of 3m/s while passing through its lowest position.
If it makes an angle of 60°with vertical, we need to calculate the speed.
It is given below.mV^2 = mV1^2+2mgh m cross 3^2 = V1^2+2*(0.5-0.5cos 60°)*9.806
= V1^2+4.903
V1 = √9-4.903
V1= 2.0 m/sec
The speed will be 2m/sec
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