A pendulum clock is 5 seconds fast at temperature of 15ºC and 10 seconds slow at a temperature of 30ºC. At what temperature does it give the correct time? (take time interval = 24 hours) (a) 18ºC (b) 20ºC (c) 22ºC (d) 25ºC
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PHYSICS
A pendulum clock is 5sec fast at temperature of 15
o
C and 10sec slow at a temperature of 30
o
C. At temperature does it give the correct time-
December 26, 2019
avatar
Abhinab Kurapati
ANSWER
T=2π
g
l
⇒T∝l
1/2
⇒
T
ΔT
=
2
1
l
Δl
and Δl=l∝Δt, linear expansion formula
⇒
l
Δl
=∝Δt
Δt= change in temperature=Final−initial
5 sec fast⇒1 hour alarm rises 5 sec before i.e., time period reduced
⇒ΔT=−5
Case I:
5 sec fast at 15
o
C
T
−5
=
z
1
∝Δt=
2
1
∝(15−t) ……..(1)
t= temperature at which correct reading.
15
o
<t<30
o
Case II:
10 sec slow at 30
o
C
⇒ΔT=10sec
⇒
T
10
=
2
1
∝(30−t) ………(2)
Heated to 30
o
C
dividing (1) by (2)
We get
−0.5=
30−t
15−t
⇒30−t=2(t−15)
⇒t=20
o
C.
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Answer:
the correct answer of the question is 20 degree Celsius. (20 degree Celsius)
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