The two ends of a rod of length L and a uniform crosssectional
area A are kept at two temperatures T₁ and T₂
(T₁ > T₂). The rate of heat transfer, dQ/dt through the rod in
a steady state is given by
(a) dQ/dt = k(T₁ - T₂)/LA
(b) dQ/dt = kLA (T₁ - T₂)
(c) dQ/dt = kA (T₁ - T₂)/L
(d) dQ/dt = kL (T₁ - T₂)/A
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Answer:
option d is the correct answer
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