Question

a pendulum clock made of a material having coefficient of linear expansion alpha= 9×10^-7/°C has a period of 0.5 second at 20 degree Celsius. If the clock is used in the climate what temperature averages 30 degree Celsius then what correction is necessary at the end of 30 days to the time given by the clock

Answer 1

Whatsup buddy,

● Answer- (a) 11.66 s

● Explanation-
# Given-
T = 0.5 s
T1 = 20 °C
T2 = 30 °C
t = 30 days = 30×24×60×60 = 2.6×10^6 s

# Formula-
Loss/gain of time in time t is given by-
∆t = 1/2 α∆Tt =
∆t = 1/2 α (T2-T1) t
∆t = 0.5 × 9×10^-7 × (30-20) × 2.6×10^6
∆t = 4.5×2.6
∆t = 11.7 s

Time lost by clock in 30 days is 11.7 s.

Hope this is useful...

Answer 2

Explanation:

a pendulum clock made of a material having coefficient of linear expansion alpha= 9×10^-7/°C has a period of 0.5 second ...

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