A pendulum completes 2 oscillation in 5s
a. what is it's time period?
b. If g=9.8 m/s
Find it's lengths
Answers
Answered by
1
2 oscillations in 5 s hence 1 oscillation in 2.5 s which is its time period
T=2π√1/g
2.5=2π√1/g
1=10×6.25/4π²=1.58m
Attachments:
Answered by
1
Explanation:
2 oscillations in 5 s hence 1 oscillation in 2.5 s which is its time period
T=2π √l/g
2.5= 2π √l/g
l=10×6.25/ 4π
=1.58m
Similar questions