Question

A pendulum has a frequency of 5 vibrations per second. An observer starts the pendulum and fires a gun simultaneously .He hears the echo from the cliff after 8 vibrations of the pendulum .if the velocity of sound in air is 340m/s find the distance between the cliff and the observer?

Answer 1

Time taken for 1 vibration = 1/5 s 

Time taken for 8 vibrations = 8/5 s 

We know,  

2d = vt 

Therfore, 

D= vt/2 [where d= distance between the observer and the cliff] 

V = velocity of sound 

T= time taken for the sound to go and return 

D = (340 * 8 / 5*2) m  

D = 272 m 

So the distance between the cliff and observer is 272

Answer 2

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