Question

a pendulum is oscillating with frequency of 10 hz the minimum time taken for by the bob to reach the main position from any extreme position is

Answer 1

Given :

Frequency of the pendulum - 10 Hz

To Find :

The minimum time taken for by the bob to reach the mean position from any extreme position.

Solution :

Frequency of the pendulum = 10 Hz

Time period of the pendulum (T) = $\frac{1}{Frequency}$

                                                      = $\frac{1}{10}$ = 0.1 sec

∴ The time taken by the bob to reach the mean position from any extreme position = $\frac{T}{4}$ = $\frac{0.1}{4}$ = 0.025 sec

Answer 2

Given:

• Frequency of pendulum is 10 Hz.

To find:

• Time taken for bob to reach mean position from extreme position?

Calculation:

First of all, let's calculate the time period of pendulum :

• Time period is the time needed to complete one full oscillation. It is the reciprocal of frequency.

$T = \dfrac{1}{f}$

$\implies T = \dfrac{1}{10}$

$\implies T = 0.1 \: sec$

• Now, one time period = 4 × (the time taken to travel from mean to extreme position)

So, the required time is :

$t = \dfrac{T}{4}$

$\implies t = \dfrac{0.1}{4}$

$\implies t = 0.025 \: sec$

So, time taken to reach mean position is 0.025 seconds.