a pendulum of length 28 CM oscillates such that 8 strings make an angle of 30 degree from the vertical when it is at one of the extreme position find the ratio of the distance to displacement of the bob of the pendulum when it move from one extreme position to the other
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Length of the pendulum(r)=28 cm
Displacement of Bob= 2rsin∅
_________________________
i.e
=2(28)sin30°
=56(1/2)
=28.
___________________
distance travelled =length of arc through the Bob travelled.
[angle subtended by the arc=30°+30°=60°]
=πr×60÷180.
=22(28)×60÷7(180)
=36,960÷1260
=29.33
=let it be 29 (approx).
_______________________
therefore
the ratio of Distance :Displacement is 29:28.
Thank You!☺️
☘️ALL THE BEST.☘️
Displacement of Bob= 2rsin∅
_________________________
i.e
=2(28)sin30°
=56(1/2)
=28.
___________________
distance travelled =length of arc through the Bob travelled.
[angle subtended by the arc=30°+30°=60°]
=πr×60÷180.
=22(28)×60÷7(180)
=36,960÷1260
=29.33
=let it be 29 (approx).
_______________________
therefore
the ratio of Distance :Displacement is 29:28.
Thank You!☺️
☘️ALL THE BEST.☘️
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